Math, asked by elizaford, 7 months ago

The equation of a line perpendicular to the line 4x-5y+3=0 and passing through the point(-3, 7) is​

Answers

Answered by Anonymous
3

Solution:-

 \rm \implies  \: given \: equation \: is \: 4x - 5y =  - 3

 \rm \implies \: given \: point \: ( - 3,7)

:- Slope of line is

 \rm \implies \:m =   \dfrac{ - a}{b}  =  \dfrac{ - 4}{ - 5}  =  \dfrac{4}{5}

Its is given that line is Perpendicular So Slope is

 \rm \implies \: \: slope \: is \: =   \dfrac{ - 1}{m}  =  \dfrac{ - 1}{ \dfrac{4}{5} }  =  -  \dfrac{5}{4}

Formula for equation

 \rm \implies(y_2 - y_1) = m(x_2 - x_1)

 \sf \: points \: is \: ( - 3,7)

By putting the value we get

 \rm \implies(y - 7) =  \dfrac{ - 5}{4} (x - ( - 3))

 \rm \implies4(y - 7) =  - 5(x + 3)

 \rm \implies4y - 28 =  - 5x - 15

 \rm \implies5x + 4y = 28 - 15

 \rm \implies5x + 4y = 13

Equation is

 \rm5x + 4y = 13

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