Question

The equation of a particle executing shm is y=2sin 40πt in m. Calculate
amplitude, angular frequency, frequency, and time period.

Answer 1

Answer:

Amplitude = 2

angular frequency = 40π rad/s

frequency = 20Hz

time period = 0.1sec

Explanation:

standard equation = Asin(ωt ± kx)

Given Equation = 2sin(40πt)

compare the given equation with standard equation

We get , Amplitude , A = 2

Angular frequency ω = 40π rad/s

And as we know that frequency = ω/2π

∴ F = 40π /2π = 20 Hz

Time period , T= 2π /ω = 2π /40π = 2/20

T = 0.1sec

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