Question

the equation of a plane through the point A(1,0,0) and perpendicular to the line x+1/2=y-3/1=z+7/-3 is​

Answer 1

let the required equation of plane through (1,0,0) be

a(x−1)+b(y−0)+c(z−0)=0.

Since, the line is perpendicular to the plane, so it is parallel to the normal to the plane.

2(x−1)+4(y−0)−3(z+1)=0⇒2x+4y−3z=5.