Question

the equation of a progressive wave for a wire is y=7sin(4t-0.02x) where x and y is in cm .find the maximum speed ​

Answer 1

Answer:

Maximum speed = Aw

A= Amplitude

W= Omega

Then - 7×4= 28cm/sec

Answer 2

The maximum speed of the wave is 28 m/s.

Explanation:

The equation of a progressive wave for a wire is given by :

$y=7\text{sin}(4t-0.02x)$..........(1)

The general equation of the progressive wave is given by :

$y=A\text{sin}(\omega t-kx)$...........(2)

On comparing equation (1) and (2) we get :

$\omega=4$

$k=0.02$

A = 7 cm

The maximum speed of the wave is given by :

$v=A\omega\\\\v=7\times 4\\\\v=28\ m/s$

So, the maximum speed of the wave is 28 m/s. Hence, this is the required solution.

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