Question

The equation of a projectile is given by Y = 13x-5². (g = 10 ms-'] Angle of projection is​

Answer 1

Answer:

Given,  → u u→ =  ^ i + 2 ^ j i^+2j^ = ux ^ i i^ + uy ^ j j^ Then ux = 1 = ucosθ  and uy = 2 = usinθ ∴ ∴ tanθ =  u sin θ u cos θ usin⁡θucos⁡θ =  2 1 21 = 2 The equation of trajectory of a projectile motion is y = x tanθ -  g X 2 2 u 2 cos 2 θ gX22u2cos2⁡θ = x tanθ -  g X 2 2 ( u cos θ ) 2 gX22(ucos⁡θ)2 ∴ ∴ y = x * 2 -  10 × X 2 2 ( 1 ) 2 10×X22(1)2 = 2x - 5x2Read more on Sarthaks.com - https://www.sarthaks.com/245323/projectile-is-given-an-initial-velocity-of-the-cartesian-equation-of-its-path-is-take-10-ms

Explanation: