Question

the equation of a projectile is y=4x-2x^2 its horitzontal range is (all quantities are in SI units and y is vertically upwards) answer is 2m how??

Answer 1

Explanation:

Equation of trajectory=4x-2x^2=2x(2-x)

Multiply and divide by 2

=4x(1-x/2)

Comparing it with general equation if trajectory ie x tan theta(1-x/R)

R=2m

Thank you!

Answer 2

Answer:

Horizontal Range = 2m

Explanation:

• Equation of projectile is given by

                       $y = 4x-2x^{2}$

                       $y =4x(1-\frac{x}{2} )$                                            (1)

• General equation of trajectory is given by

             $y =xtan\alpha (1-\frac{x}{R} )$                                                (2)

on comparing equation 1 and 2 ,

we get,

         (  Horizontal Range )  $R = 2m$