Question

the equation of a projectile is Y is equal to 4 x minus 2 x square if then its horizontal range is​

Answer 1

Explanation:

l think , lt is the ans of this question

Answer 2

Answer:

Horizontal range is 2 units.

Explanation:

We have

$y = 4x- 2x^{2}$......................(1)

we know that the general equation of projectile motion is given by

$y =xtan\theta - \dfrac{gx^{2} }{2(vcos\theta )^{2} }$...........(2)

From (1) and (2) we get,

$g = 4(vcos\theta)^{2}$................(3) and $4 = tan\theta$........................(4)

we know that the horizontal range is given by

$R = \dfrac{(sin2\theta) (v) ^{2} }{g}$..........................(4)

using (3) and (4) we get,

$R = \dfrac{v^{2}2sin\theta cos\theta}{4v^{2}(cos\theta)^{2}}$

$R = \dfrac{tan\theta }{2} = \dfrac{4}{2} = 2$

So, horizontal range is 2 units.