Question

The equation of a projectile is y = $\sqrt{3x}-\frac{gx^{2}}{2}$The angle of projection is given by(a) tan θ = $\frac{1}{\sqrt{3}}$(b) tan θ= $\sqrt{3}$(c) $\frac{\pi}{2}$(d) zero.

Answer 1

I think ur answer is b part
hope it helps u dear friend