Question

The equation of a straight line equally inclined to the axes and equidistant from the points (1, -2) and (3, 4) is (1) x + y + 1 = 0 (2) x - y + 1 = 0 (3) x - y - 1 = 0 (4) x + y - 1 = 0​

Answer 1

Answer:

$\huge \fbox\red{anSweR}$

=> Equally inclined to the axes, means that the slope of the line must be: m=1 [parallel to y=x]

=> the line pases through the midpoint of the segment joining (−3,−2) and (3,4)

=> point-slope form:(y−1)=m(x−0)

=> y−1=1×x

=> i.e.x−y+1=0

Answer 2

Answer:

$\huge \fbox\red{anSweR}$

=> Equally inclined to the axes, means that the slope of the line must be: m=1 [parallel to y=x]

=> the line pases through the midpoint of the segment joining (−3,−2) and (3,4)

=> point-slope form:(y−1)=m(x−0)

=> y−1=1×x

=> i.e.x−y+1=0