Question

The equation of a straight line is given by 3x -2y-6=0. Find the:
(i) gradient of the line
(ii) y-intercept

Answer 1

Answer:

Correct option is

B

3x - y + 1 = 0

Equation of a straight line is

y=mx+c

Where m is the slope of the line and c is the y intercept

Given,

m=3,c=1

∴y=3x+1

=>3x−y+1=0

Answer 2

Answer:

Gradient of the line =  $\frac{3}{2}$

Y- intercept =  -3

Step-by-step explanation:

Given,

The equation of the straight line is 3x - 2y - 6 = 0

Required to find,

(i) gradient of the line

(ii) y-intercept

Formula used,

The general form an equation of a straight line is y = mx +c  , where

'm'  = The slope/gradient of the line

c =   Y-intercept.

Here, the given equation is

3x - 2y - 6 = 0

2y = 3x -6

y = $\frac{3}{2}x - 3$

Comparing this equation with y = mx +c, we get

m = $\frac{3}{2}$ and c = -3

Hence,

Gradient of the line = m = $\frac{3}{2}$

Y- intercept = c = -3