The equation of a straight line is y = 3x - 8, find the coordinates of the point of intersection of the line y = 3x - 8 with the line y = x
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Step-by-step explanation:
Given, line is y=3x−15 intersects the line y=mx+8 in third quadrant
Let the point of intersect in third quadrant coordinates of point is (x,−y)
It is the same point for Line 1 and for Line 2. So, at the point of intersection the (x,−y) coordinates for Line 1 equal the (x,−y) coordinates for Line 2.
Since at the point of intersection the two y-coordinates are equal,
∴3x−15=mx+8
⇒3x−mx=8+15
⇒x(3−m)=23
⇒x=3−m23
Put value x=3−m23
Then y=3(3−m23)−15
Then m is a positive real number if inter sect third quadrant.
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