Question

The equation of a straight line is y = 3x - 8, find the coordinates of the point of intersection of the line y = 3x - 8 with the line y = x

Answer 1

Step-by-step explanation:

Given, line is y=3x−15 intersects the line y=mx+8 in third quadrant

Let the point of intersect in third quadrant coordinates of point is (x,−y)

It is the same point for Line 1 and for Line 2. So, at the point of intersection the (x,−y) coordinates for Line 1 equal the (x,−y) coordinates for Line 2.

Since at the point of intersection the two y-coordinates are equal, 

∴3x−15=mx+8

⇒3x−mx=8+15

⇒x(3−m)=23

⇒x=3−m23

Put value x=3−m23

Then y=3(3−m23)−15

Then m is a positive real number if inter sect third quadrant.