Question

The equation of a straight line passing through (3,-1) and having intercepts equal in magnitude but opposite in sign is
Pls help...​

Answer 1

Answer:

The equation of the required line is

x-y-4=0

Step-by-step explanation:

The equation of straight in intercept form is

$\frac{x}{a}+\frac{y}{b}=1$......(1)

Given: b=-a

(1) becomes

$\frac{x}{a}+\frac{y}{-a}=1$

$\frac{x}{a}+\frac{-y}{a}=1$

$\frac{x-y}{a}=1$

$x-y=a$

But this line passes through (3,-1)

3+1=a

⇒ a=4

∴The equation of the required line is

x-y-4=0

Answer 2

Given : Point(3,-1)

To find :  equation of a straight line

Explanation:

Let the length of the intercept by the straight line from both the coordinates axes be a

the equation of the line is in the form of

$\frac{x}{a}+\frac{x}{-a}=1\\\\x-y=a..(1)$

according to the question the line (1) passes through (3,-1)

then

a = 3-(-1) = 4

thus

The equation of the line x-y-4 =0

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