Question

the equation of a straight line passing through points (3,4) and (5,6) is​

Answer 1

Answer:

x - y + 1 =0

Step-by-step explanation:

Slope(m) of the line = (y₂ - y₁)/(x₂ - x₁)

                   = (6 - 4)/(5 - 3)

                   = 2/2 = 1

   Using,

⇒ (y - y₁) = m(x - x₁)

⇒ y - 4 = 1(x - 3)

⇒ y - 4 = x - 3

⇒ x - y + 1 = 0

  Require equation of the line is x - y + 1=0

I took (x₁, y₁) = (3, 4).  It can be solved using any point lying on that line.

(5, 6) would give the same result, as it lies on the same line