Math, asked by rnithin961, 1 year ago

The equation of a straight line passing through the point (1,2)and inclined at 45degrees to the line y=2x+1

Answers

Answered by SanyamTaneja
7
tan45=(m-1/2)/(1+m/2)
1+m/2=m-1/2. tan45=1
3/2=m/2
m=3

slope of required lime=3
using 1 point form,

3=(y-2)/(x-1)
3x-3=y-2
3x-y-1=0

is our required equation
Answered by yogeshkumar49685
0

Concept: A straight line's general equation is y = mx + c, where m is the gradient and y = c  is the value at which the line intersects the y-axis. On the y-axis, this quantity c is known as the intercept.

Given:

Equation of straight-line pass-through (1,2)

\theta= 45°, inclination to y=2x+1

To find:

equation of a straight line

Solution:

Let the equation of the straight line be y = mx + c

The angle between two lines is given by

tan \theta =\frac{m_{2} - m_{1} }{1 + m_{1} m_{2} }

tan45^{\°}=\frac{m-2}{1+2m}\\ m-2=2m+1\\m=-3\\

Therefore, the value of y=-3x+c.

Value of c=2+3=5

The equation of a straight line is y+3x=5.

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