Question

the equation of a straight line passing through the point (-5 -6) and (3,10)

Answer 1

Answer:

we know that equation of straight line with two points (x1,y1) and (X2,y2) is y-y1= (y2-y1)X2 -(x-x1)x1..

y-6=(10-6)3-(X+5)(-5)

y-6= 12-(5x-25)

y-6=12-5x+25

5x-y+6+37=0

5x-y+43=0

Answer 2

Answer:

y = 2x + 4

hope this brings clarity to your problem

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