Physics, asked by wipronreddy, 6 months ago

The equation of a trajectory of a projectile isy = 8.1 - 422. The maximum height of the projectile is
(A) 8 m
(B) 6 m
(C) 2 m
(D) 4 m​

Answers

Answered by Anonymous
1

For maximum height:

dxdy=0⇒dxd(10x−95x2)=0

⇒10−910x=0

⇒x=9 m

Answered by avanimudabagil12
0

Answer:

The answer is a option A

Mark me Brainliest

Similar questions