Question

The equation of a transverse wave is given by y= 0.05sin21 (0.4x-St) where x and y
are in m and time in s. The wavelength of the wave is
a) 2.5m (b) 5m
(c) 2m
(d)lm
1

Answer 1

Explanation:

K = 2π/lemda

K = 21×.4 = 8.4lemda = 2π/8.4 = .74m

Thanks for Reading

Answer 2

So we are given....

y = 0.05sin 21(0.4x - St)

y = 0.05sin (8.4x- 21St)

Compare it with.....

y = a sin (Kx - omega t)

So a = amplitude = 0.05

k = 8.4 = 2π/lambda

Therefore.. lambda = 2π/k

Lambda = 2π/8.4

Lambda = 0.7 m