Question

The equation of a transverse wave travelling on a rope is given by y = 10
sint(0.01x-2.00t) where y and x are in cm and t in seconds. The maximum
transverse speed of a particle in the rope is about
1)62.8 cm/s 2)75 cm/s
3) 100 cm/s 4) 121 cm/s​

Answer 1

Explanation:

Y =Asin(kx-wt)

Y=10sin(0.01x-2.00t) compare both equations

A =10cm, k=0.01 , w=2.00

V=w/k

V=2.00÷0.01

v=200cm