Question

the equation of an alternating emf is e=160sin(120pai t). find the peak value of its emf and its frequency​

Answer 1

The peak value of emf and its frequency are 160 V and 60 1/s respectively

• The equation of an alternating emf is,

e = 160sin( 120πt )

• We can clearly see that the amplitude of emf is 160 i.e peak value of AC emf
• Also, the value of angular frequency can be found out by comparing it with the coefficient of t i.e 120π
• We know that frequency, f = w/2π

Where w = angular frequency

f = 120π / 2π

• f = 60