Question

The equation of an alternating voltage is equal to 20 sin omega t + 5 by 6 and the equation of the current in the circuit is equal to 10 sin omega t minus 5 by 6 impedance of the circuit is

Answer 1

Z=E0I0  

E0=220

I0=10

Z=22010

=22ohms

ϕ=[π6−(−π6)]

=π3

Power =E02–√×I02–√cosϕ

=2202–√×102–√ cosπ3

=550W

Answer 2

The equation of an alternating voltage is

and the equation of the current in the circuit is

. Then the impedance of the circuit is 550 W