Question

The equation of an object moving in a straight path is x = 8 + 4t - 2t² According to where is in 3 meters and in t seconds. So find the distance traveled by t = 0 to 4 seconds.​

Answer 1

Explanation:

Given:

x=16t−2t

2

Comparing with second equation of motion:

s=ut+

2

1

at

2

It can be concluded that:

u=16 m/s,a=4 m/s

2

Now, using first equation of motion:

v=u+at

v=16−4t

For v=0 we get, t=4s

Here, direction of velocity will reverse. So total distance travelled will be the sum of displacement in first four seconds and displacement in next four seconds.

Now,

Displacement at

t=0,x=0

t=4,x=32

t=8,x=0

∴ Distance = (distance from x=0 to x=32) + (distance from x=32 to x=0)

∴ Distance =32+32=64 m

Solve any question of Motion in a Straight Line with:-

Answer 2

Answer:

Given:

x=16t−2t

2

Comparing with second equation of motion:

s=ut+

2

1

at

2

It can be concluded that:

u=16 m/s,a=4 m/s

2

Now, using first equation of motion:

v=u+at

v=16−4t

For v=0 we get, t=4s

Here, direction of velocity will reverse. So total distance travelled will be the sum of displacement in first four seconds and displacement in next four seconds.

Now,

Displacement at

t=0,x=0

t=4,x=32

t=8,x=0

∴ Distance = (distance from x=0 to x=32) + (distance from x=32 to x=0)

∴ Distance =32+32=64 m

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Explanation:

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