Question

The equation of circle having center at (3,2) and
circle tangent to x-axis is

​

Answer 1

Answer:(

x

−

2

)

2

+

(

y

−

3

)

2

=

9

Explanation:

the equation of a circle in standard form is

∙

x

(

x

−

a

)

2

+

(

y

−

b

)

2

=

r

2

where

(

a

,

b

)

are the coordinates of the centre and r

is the radius

here

(

a

,

b

)

=

(

2

,

3

)

r is the vertical distance from the x-axis to the centre

r

=

y-coordinate of centre

=

3

(

x

−

2

)

2

+

(

y

−

3

)

2

=

9

←

equation of circle

Step-by-step explanation: