The equation of circle having center at (3,2) and
circle tangent to x-axis is
Answers
Answered by
3
Answer:(
x
−
2
)
2
+
(
y
−
3
)
2
=
9
Explanation:
the equation of a circle in standard form is
∙
x
(
x
−
a
)
2
+
(
y
−
b
)
2
=
r
2
where
(
a
,
b
)
are the coordinates of the centre and r
is the radius
here
(
a
,
b
)
=
(
2
,
3
)
r is the vertical distance from the x-axis to the centre
r
=
y-coordinate of centre
=
3
(
x
−
2
)
2
+
(
y
−
3
)
2
=
9
←
equation of circle
Step-by-step explanation:
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