Question

the equation of circle passing through the origin and point of intersection of circle x²+y²-2x+4y-20=0 and line x+y-1=0 is​

Answer 1

Answer:

equation of circle passing through point of intersection of given circle and the line is of the form

x²+y²-2x+4y-20 +A(x+y-1)=0. where 'A' is a parameter

now simplifying we get:

x²+y²+x(A-2)+y(A+4)-20-A=0

now also given that this circle passes through origin (0,0) therefore put x=0 and y=0 in the equation we get

A=-20

now by putting A=-20 in the equation we get the required equation of the circle.

x²+y²-22x-16y=0