Question

The equation of circle passing through the points (1.1), (2, -1)(3.2) is
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Answer 1

Answer:

x²+y²-5x-y+4=0

Step-by-step explanation:

Let the equation of the circle is:

x²+y²+cx+dy+e=0

This passes through (1,1),(2,-1) and (3,2) thus

1+ 1 + c + d + e=0

c+d+e=-2...........................(1)

4+1+2c-d+e=0

2c-d+e=-5............................(2)

9+4+3c+2d+e=0.

3c+2d+e =-13...............(3)

(1) -(2) gives  c-2d=-3........(4)

(3) -(2) gives c+3d=-8........(5)

(4)-(5) gives

5d =-5 ,d=-1

from(4) c+2=-3,c=-5

Putting value of c and d in(1)

-5-1+e=-2, e=6-2=4

Thus the equation of the circle is:

x²+y²-5x-y+4=0

Answer 2

Answer:

X² +Y² -5X - Y = -4

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