Math, asked by rohildalal5, 9 months ago

The equation of circle with centre (1,2) and tangent x + y - 5= 0 is:
(a) x² + y² + 2x - 4y + 6 = 0
(b) x² + y² - 2x - 4y + 3 = 0
(C) x² + y² - 2x + 4y + 8 = 0
(d) x² + y² – 2x – 4y + 8 = 0​

Answers

Answered by harichandan31729
2

Step-by-step explanation:

perpendicular distance from centre to tangent is radius so,

perpendicular distance = √2=radius

so the équation be

 {(x - 1)}^{2}  +  {(y -2) }^{2}  = 2

expand the équation

then B is ur answer

mark as brainliest answer

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