Question

the equation of line AB is y=5x+1. write an equation of a line parallel to line AB in slope-intercept form that contains point (4,5)

Answer 1

Answer:

slope of line AB = 5

Let the required line be 'l'.

since AB is parallel to 'l'.

so slope of 'l' = slope of AB = 5.

So, the required equation of line which passes through (4,5) and having slope 5 is given by

y - 5 = 5(x - 4).........[using slope point form]

y = 5x - 20 + 5

y = 5x - 15.