Question

The equation of line l is 3x+4y=7, and the equation of line q is 4x-3y=0. Which statement about the two lines is true?

Answer 1

Answer:

both the lines L and Q are perpendicular to each other.

Step-by-step explanation:

equation of line l

3x+4y=7

we know that,

y=mx+c

3x+4y=7

4y=-3x+7

y=-3x/4+7/4

slope of this equation = -3/4

equation of line q,

y=mx+c

4x-3y=0

-3y=-4x

y=-4x/-3

y=4x/3

slope of line =4/3

now, we have to check that which statement is true for these slopes,

if the lines are perpendicular then,

m1*m2=-1

-3/4*m2=-1

m2=4/3

therefore,

m2=slope of line q

so, the lines are perpendicular to each other.

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