The equation of line m is 5x−3y=2. What is the slope of a line that is perpendicular to line m?
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slop of this line 5/3
perpendicular is negative reciprocal so,
-3/5, will be the slop of the line
perpendicular is negative reciprocal so,
-3/5, will be the slop of the line
sprao534:
slope of the line m=5/3
slope of perpendicular line= - 3/5
yes
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rearranging the equation of the line given in the form of y = mx + c ,we get...
y = 5/3x - 2/3
comparing with y = mx+c (eq. of a straight line)
m1 = 5/3
let slope of the line that is perpendicular to line m be m2.
we know that
m1 × m2 = -1
(where m1 and m2 are slopes of line perpendicular to each other)
substituting the values of m1 and m2,
we get,
5/3 × m2 = -2
m2 = -6/5 (answer)
y = 5/3x - 2/3
comparing with y = mx+c (eq. of a straight line)
m1 = 5/3
let slope of the line that is perpendicular to line m be m2.
we know that
m1 × m2 = -1
(where m1 and m2 are slopes of line perpendicular to each other)
substituting the values of m1 and m2,
we get,
5/3 × m2 = -2
m2 = -6/5 (answer)
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