Question

the equation of line perpendicular to PQ that passes through the point ( 2,3) ( 10,11 )(6,-2)​

Answer 1

Step-by-step explanation:

Given a line is perpendicular to the line 4x−3y=10 .... (i) and passing through (2,3)

Now, slope of the above line (i) is m=

3

4

Let the slope of perpendicular line be m

1

then m

1

m=−1

⇒m

1

=

4

−3

Then the equation with slope will be y=

4

−3

x+c

The above line is passing through (2,3)

⇒3=

4

−3

×2+c

⇒c=

2

9

Therefore the required equation of line is y=

4

−3

x+

2

9

4y+3x=18