Question

the equation of line which intersects the x-axis & y-axis in (3,0)&(0,-2) respectively to​

Answer 1

Answer:

in (3,0)

x=3 AND y=0

3+0=3

therefore here, x+y=3

multiplying both sides by -2 because the sum in point(0,-2) us -2.

we have,

-2(x+y)=-2*3

-2x-2y=-6 -----(1)

in (0,-2)

x=0 AND y=-2

0+(-2)=-2

therefore here, x+y=-2

multiplying both sides by 3 because the sum in point(3,0) us 3.

we have,

3(x+y)=3*-2

3x+3y=-6 -----(2)

since, RHS of (1) and (2) are equal

therefore, equating LHS of (1) and (2)

we have,

3x+3y=-2x-2y

3x+2x=-3y-2y

5x=-5y

5x/-5=y

-x=y

-x+y=0

there equation is -x+y=0

(Note : i am not sure about the answer so please once check it also before writing it)