The equation of motion of a ground to ground
projectile in xy plane is y = 6x-4/3x2, where x and y are
in metre. The horizontal range of the projectile is
9 m
2 m
3.5 m
4.5 m
Answers
Answered by
4
Answer:
Here answer is 4.5 m
Explanation:
Here in the Projectile plane we have to find ground to ground Projectile thus here our y=0 ,ok ;
Now , when we put 0 in y we get ;
•0= 6x-4/3ײ
•6x=4/3x²
•6=4/3x
•x=18/4
Thus;x=4.5m
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