Physics, asked by nagendrarishish3, 9 months ago

The equation of motion of a ground to ground
projectile in xy plane is y = 6x-4/3x2, where x and y are
in metre. The horizontal range of the projectile is

9 m
2 m
3.5 m
4.5 m​

Answers

Answered by guruji99099
4

Answer:

Here answer is 4.5 m

Explanation:

Here in the Projectile plane we have to find ground to ground Projectile thus here our y=0 ,ok ;

Now , when we put 0 in y we get ;

•0= 6x-4/3ײ

•6x=4/3x²

•6=4/3x

•x=18/4

Thus;x=4.5m

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