Question

The equation of motion of a projectile are given by x=36t meters and 2y=96,t=9.8t square meters .Tge angke of projection is

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Answer 1

Answer:

angle of projection = 53°

Explanation:

acceleration in x-direction = 0

acceleration in y-direction = 9.8 m/sq-sec downward

x = 36 t

=> initial speed in x-direction = 36 m/s......(1)

=> ux = 36 m/s .....

now,

2y = 96t - 9.8 t^2

=> y = 48t - (1/2) 9.8 t^2

using eqn, s = ut + (1/2) a t^2

initial speed in y-direction = 48 m/s ....(2)

=> uy = 48 m/s .....

now,

tan (theta) = uy / ux = 48/36 = 4/3

=> theta = atan (4/3) = 53°

hence, angle of projection = 53°

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hope, it helps you.

Answer 2

Explanation:

x=36t so t=x/36

put this value in equation of u

y=48*x/36-9.8*x/36

compare this with equation of trajectory i.e y =xtan θ (1-x/r )

you will get tan θ  and hence θ