Question

The equation of motion of a projectile is y = 12 x 0.75 x2. The horizontal component of velocity is 3 m/s. Given that acceleration due to gravity (g) = 10 m/s2. Then the range of the projectile i

Answer 1

Answer:

Then, x=0 gives x coordinate of the point of projection and 12=3/4x or x=16 m ... The horizontal component of velocity is 3m/s. ... 12 =3/4x or x=16 m gives the range of the projectile.