Question

The equation of motion of a projectile is y = 122 – 2? What is the range of the projectile?
12 m
O 16 m
O 20 m
O 24 m​

Answer 1

Answer:

Correct option is

A

16

Given, y=12x−

4

3

x

2

The general equation of a projectile motion is given by, y=xtanθ−

2u

2

cos

2

θ

g

x

2

Comparing both equation, we get tanθ=12 and

2u

2

cos

2

θ

g

=

4

3

Now, u

2

cos

2

θ=(4/3)(g/2)=(4/3)(10/2)=40/6=20/3

⟹ ucosθ=

20/3

Also, from tanθ=12

We get

cosθ

sinθ

=12

⟹ usinθ=12ucosθ=12×

20/3

Range of a projectile motion is given by, R=

g

u

2

sin2θ

R=

g

u

2

(2sinθcosθ)

=

10

2(12

20/3

)(

20/3

)

=

3×10

20×24

=16 m