the equation of motion of partical performing SHM is x=3sin 6πt in cm. determine its amplitude of motion , frequency,velocity and accelerationat the position of maxmum displacement.
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Answer:
f=12Hz
w=2πf=24π rad/sec
A=4cm;x=2cm
x=Asinϕ
2=4sinϕ
Thus ϕ= 6π
Thus
x=0.04sin(24πt+ )
6π
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