Question

The equation of motion of particle which started at t=0 is given by x=5sin(20t+pi/3) when does particle come to rest

Answer 1

dx/ dt= 5 cos( 20t + pi/3) × 20 =0

20 t + pi/3 = pi/2

20 t = pi/6
t = pi/120

Answer 2

Answer:PI/120

Explanation:It is initially at pi/3.

and it will come to rest at first on pi/2 .

therefore angle to be covered is (pi/2-pi/3=pi/6) .here ω=20 .so pi/6× 1/20 =pi/120(answer)