Question

The equation of normal to the circle x^2+y^2-4x+4y-17=0 which passes through 1,1

Answer 1

Answer:

$3x + y = 4.$

Step-by-step explanation:

${x}^{2} + {y}^{2} - 4x + 4y - 17 = 0 \\ \\ centre \: is \: at \: (2 \: \: \: \: \: \: - 2) \\ \\ equation \: of \: the \: normal \: is \: \: \: (y - 1) = ( \frac{1 + 2}{1 - 2} )(x - 1) \\ \\( y - 1) = - 3(x - 1) \\ \\ 3(x - 1) = - (y - 1) \\ \\ 3x - 3 + y - 1 = 0 \\ \\ 3x + y = 4.$