Question

The equation of pair of tangents
drawn from the point, (0, 1) to the
circle x2+ y2 - 2x+ 4y 0 is -
(1) 4x2-4y2 + 6xy + 6x +8y-4 0
(2) 4x2-4y2 +6xy-6x +8y-4 = 0
(3) 4x2-4y2+3xy 3x +2y 4 0
(4) 4x2-4y2 +6xy - 6x +8y + 4 =0
plz answer correct ​

Answer 1

$T ^{2} = SS _{11}$

$\\ (y - x + 2(y + 1)) ^{2} =(5)( {x}^{2} + {y}^{2} - 2x + 4y)$

$\\ 9 {y}^{2} + {x}^{2} + 4 - 6xy + 12y - 4x - 5 {x}^{2} - 5 {y}^{2} + 10x - 20y= 0$

$\\ - 4 {x }^{2} + 4 {y}^{2} - 6xy + 6x - 8y + 4 = 0$

$\sf option \: (2)$

$\boxed{4 {x}^{2} -4 {y}^{2} + 6xy - 6x + 8y - 4 = 0 \: \: \: \: \: \: \: \: }$