Question

the equation of parabola whose vertex is (0,0),axis is along x-axis and passes through the point (-2,4)​

Answer 1

Answer:

The equation is y^2 = -2ax.

Step-by-step explanation:

The equation of parabola is y^2 = 4ax.

Here the parabola passes through the point (-2,4).

So , 16 = -8a

=>   a = -2.

The equation is y^2 = -2ax.

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Answer 2

Answer:

equation of parabola is , $y^2=-8x$

Step-by-step explanation:

Given :- vertex of parabola is (0,0) along x axis , passes through ( -2,4) .

To find :- Equation of parabola .

Solution :-

Since the vertex of the parabola is (0,0) .

and passes from (-2,4) .

Thus the equation of parabola ( general ) will satisfy the points .

General equation we know is , $y^2=4ax$ .

By substituting the value of x = -2 , y = 4 .

we get

$4^2 = 4a(-2) \\16 = -8a \\a = -2 .$

Therefore the equation we obtained is ,

$y^2 = 4(-2)x \\y^2 = -8x$

Answer , equation of parabola is , $y^2=-8x$

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