The equation of parabola with vertex at origin the axis is along x-axis and passing through the point (2, 3) is
Answers
EXPLANATION.
Equation of parabola with vertex at origin the axis is along the x-axis.
passing through the point = (2,3).
As we know that,
Equation of parabola = y² = 4ax.
Substitute the value of x and y in equation, we get.
⇒ (3)² = 4a(2).
⇒ 9 = 8a.
⇒ a = 9/8.
Substitute this value into main equation, we get.
⇒ y² = 4(9/8)x.
⇒ y² = (9/2)x.
⇒ 2y² = 9x.
MORE INFORMATION.
Length of intercept.
The length of intercept made by line y = mx + c on the parabola,
y² = 4ax is AB = 4/m² √a(1 + m²)(a - mc).
Conditions of tangency.
(1) = The line y = mx + c touches a parabola y² = 4ax then c = a/m.
(2) = The line y = mx + c touches a parabola x² = 4ay if c = -am².
Equation of tangent.
(1) = Point form = The equation of a tangent to the parabola y² = 4ax at the point (x₁, y₁) is yy₁ = 2a(x + x₁) or T = 0.
(2) = Parametric form = The equation of the tangent to the parabola at t.
that is (at², 2at) is ty = x + at².
(3) = Slope Form = The equation of the tangent of the parabola y² = 4ax is y = mx + a/m.
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★ The axis is along x-axis and passing through the point (2, 3).
★ The equation of parabola with vertex at origin the axis is along x-axis and passing through the point (2, 3) is ?
★ The equation of parabola with vertex at origin the axis is along x-axis and passing through the point (2, 3) is
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★ The equation of parabola with vertex at origin the axis is given by what?
★ The equation of parabola with vertex at origin the axis is given by
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~ Now we have to put the values according to the dimension..!
~ Now let's us imply the value of a as 9/8 in that dimension again to get correct and full solution..!
- (× = ÷) ; (÷ = ×)
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