Question

The equation of plane passing through the points (-1,1,1), (2, -1,3) and (2, 1,0) is ​

Answer 1

Answer:

Equation of the plane passing through (1,0,2),(−1,1,2),(5,0,3) is given by

∣

∣

∣

∣

∣

∣

∣

∣

x−x

1

x

2

−x

1

x

3

−x

1

y−y

1

y

2

−y

1

y

3

−y

1

z−z

1

z

2

−z

1

z

3

−z

1

∣

∣

∣

∣

∣

∣

∣

∣

=0

⇒

∣

∣

∣

∣

∣

∣

∣

∣

x−1

−1−1

5−1

y−0

1−0

0−0

z−2

2−2

3−2

∣

∣

∣

∣

∣

∣

∣

∣

=0

⇒

∣

∣

∣

∣

∣

∣

∣

∣

x−1

−2

4

y

1

0

z−2

0

1

∣

∣

∣

∣

∣

∣

∣

∣

=0

⇒x+2y−4z+7=0