The equation of position of an object is given by 8t³+2t²+9t-5. Calculate the avarage acceleration of the object in the time interval, t=1second & t=3second.
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Answer:
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Explanation:
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Answered by
1
Answer:
A = 3t - 4t2dv/dt = 3t - 4t2
dv = (3t - 4t2)dt
Integrate
v = 3t2/2 - 4t3/3
At t = 1s
v = 3/2 - 4/3
v = 0.166m/s
Explanation:
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