Question

the equation of projectile is y = 16x-x²/4 the horizontal range is​

Answer 1

Answer:

To find the horizontal range. Put value of y to be ZERO as in equation of trajectory when ∆y is ZERO x = R i.e Horizontal Range

so, 0=16x-x²/4

16x = x²/4

x = 16 × 4

x = 64m

Answer 2

Answer:

ANSWER

horizontal range is when the parabola cross the axis. it is going to cut x -axis at two points and the distance between them is the range.

y=16x−

4

x

2

0=16x−

4

x

2

x

1

=0 and x

2

=64 are two roots of above equation

therefore range is R=x

2

−x

1

=64−0=64m