Question

The equation of stationary wave is given by Y = 0.05 cos (2πx)sin(100πt).(2πx)sin(100πt).
Find the distance between two successive nodes . Here x and y are in S.I. units.
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Answer 1

Answer:

distance between two successive nodes is 0.5 m

Explanation:

Equation of stationary wave is given as

$Y = 0.05 cos(2\pi x)sin(100\pi t)$

now we know that angular wave number of the wave is given as

$k = \frac{2\pi}{\lambda}$

so we have

$2\pi = \frac{2\pi}{\lambda}$

$\lambda = 1 m$

now we know that distance between two successive nodes is always equal to half of the wavelength

So we will have

$d = 0.5 m$

#Learn

Topic : Standing waves

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