Question

The equation of straight line passing through point of intersection of the lines x+2y=1,2x-y+1=0 and perpendicular to y=2x+2 is

Answer 1

Answer:

x+2y=1

2x-y=-1

x+2y=1

4x-2y=-2

5x=-1,x=-1/5,,2y=1+1/5=6/5,y=6/10=3/5

the intersection point is (-1/5,3/5)

y=2x+2

2x-y+2=0

slope=-2/-1=2

required lines slope is -1/2 and the required line is

y-(3/5)=-1/2(x+1/5)

5y-3/5=-1/2(5x+1/5)

5y-3=-5x-1/2

10y-6+5x+1=0

5x+10y-5=0

x+2y+1=0