Question

The equation of straight line
passing through the point (-2,-4)
and parallel to the line 3x+7y+1=0
O 3x-7y-34=0
O 2x+7y-34=0
O 2x-7y+34=0
O 3x+7y+34=0​

Answer 1

Required line is of form 3x+7y+k=0

where k is constant

since line is passing through the point (-2,-4)

3(-2)+7(-4)+k=0

-6-28+k=0

-34+k=0

k=34

therefore the answer is 3x+7y+34=0