Question

The equation of straight line, perpedicular to 3x – 4y = 6 and forming a triangle of area 6 square

units with co-ordinate ares is [ ]

a) 4x + 3y = 12
b) 4x + 3y + 24 = 0
c) 3x + 4y = 12
d) x – 2y =6
The line passing through (3, 3) and (7, 6) cut the axes at A, B, then length of AB = [ ]

a) 4/5

b) 5/4

c) 7/4

d) 4/7​

Answer 1

option (a)is the correct answer