the equation of straight line, perpendicular to 3x+4y-6=0 and forming a triangle of area 6 square uniths with co ordinate area is
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Hey Buddy here's ur answer
given equation is 3x-4y=6
we rewrite the equation , 4y=3x-6
y=(3/4)x-3/2
in these equation,slope=3/4
the coordinating point here is (0,-3/2)
set y=0 then ,0=(3/4)x-3/2
3/4x=3/2
x=2
here the coordinating point is (2,0)
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