Question

the equation of tan gent to the curve Y​

Answer 1

Answer:

The equation of the tangent to curve y = be-x/a at the point where it crosses y – axis is

1) ax + by = 1

2) ax – by = 1

3) (x / a) – (y / b) = 1

4) (x / a) + (y / b) = 1

Solution: (4) (x / a) + (y / b) = 1

y = be-x/a

Since the curve crosses the y-axis, y = b

dy / dx = (- b / a) e-x/a

At point (0, b), (dy / dx)(0,b) = – b / a

The equation of the tangent is y – b = (- b / a) (x – 0)

(x / a) + (y / b) = 1

Answer 2

Answer:

The equation of the tangent of curve y =be^(-x/a) at the point where it crosses y-axis is