Question

the equation of tangent drawn to the curve y=sin x at the point (0,6) is​

Answer 1

Answer:

I also don't know tell me

Answer 2

Step-by-step explanation:

Given curve

$y = \sin(x)$

we know that the derivatives gives slope of tangent of curve

$\frac{dy}{dx} = \frac{d}{dx} ( \sin(x) ) \\ \\ \frac{dy}{dx} = \cos(x)$

at point (0,6)

$slop e\: of \: \: tengent\\ \frac{dy}{dx} = \cos(x) \\ \\ at \: \: x = 0 \\ \\ \frac{dy}{dx} = \cos(0) = 1$

Now eq of tangent

$(y - y _{1}) = \frac{dy}{dx} (x -x _{1}) \\ \\ (y - 6) = 1( x - 0) \\ \\ y - 6 = x \\ \\ y - x = 6$

Required equation